document.write( "Question 614366: Pipe 1 can fill a tank in 4 hours. pipes 1 and 2 together can fill it in 3 hours. pipes 2 and 3 can fill it in 4 hours . How much time would pipe 2 alone and how much time would pipe 3 alone require to fill the tank? \n" ); document.write( "
Algebra.Com's Answer #386520 by lwsshak3(11628)\"\" \"About 
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Pipe 1 can fill a tank in 4 hours. pipes 1 and 2 together can fill it in 3 hours. pipes 2 and 3 can fill it in 4 hours . How much time would pipe 2 alone and how much time would pipe 3 alone require to fill the
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\n" ); document.write( "let x=hrs pipe 2 can do the job alone
\n" ); document.write( "1/x=its work rate
\n" ); document.write( "let y=hrs pipe 3 can do the job alone
\n" ); document.write( "1/y=its work rate
\n" ); document.write( "1/4=work rate of pipe 1
\n" ); document.write( "sum of individual work rates=work rate when working together
\n" ); document.write( "..
\n" ); document.write( "1/4+1/x=1/3
\n" ); document.write( "1/y+1/x=1/4
\n" ); document.write( "subtract
\n" ); document.write( "1/4-1/y=1/3-1/4
\n" ); document.write( "-1/y=1/3-1/4-1/4=4/12-6/12=-2/12=-1/6
\n" ); document.write( "y=6
\n" ); document.write( "1/x=1/3-1/4=4/12-3/12=1/12
\n" ); document.write( "x=12
\n" ); document.write( "ans:
\n" ); document.write( "hrs pipe 2 can do the job alone=12
\n" ); document.write( "hrs pipe 3 can do the job alone=6
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