document.write( "Question 614351: Joe is 10 years older than James. In 8 years, twice Joe's age will equal three times James's age. How old is each now? \n" ); document.write( "

Algebra.Com's Answer #386519 by Maths68(1474) $\"\"$ $\"About$

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Let
\n" ); document.write( "Present age of Joe = x
\n" ); document.write( "Present age of James = y\r
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\n" ); document.write( "\n" ); document.write( "Joe is 10 years older than James
\n" ); document.write( "x=y+10..............(1)\r
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\n" ); document.write( "\n" ); document.write( "In 8 years
\n" ); document.write( "Joe will be = x+8
\n" ); document.write( "James will be = y+8\r
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\n" ); document.write( "\n" ); document.write( "Then
\n" ); document.write( "twice Joe's age will equal three times James's age
\n" ); document.write( "2(x+8)=3(y+8)
\n" ); document.write( "2x+16=3y+24
\n" ); document.write( "2x-3y=24-16
\n" ); document.write( "2x-3y=8.................(2)\r
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\n" ); document.write( "\n" ); document.write( "Substituent the value of x from (1) to (2)
\n" ); document.write( "2x-3y=8
\n" ); document.write( "2(y+10)-3y=8
\n" ); document.write( "2y+20-3y=8
\n" ); document.write( "2y-3y=8-20
\n" ); document.write( "-y=-12
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\n" ); document.write( "y=12\r
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\n" ); document.write( "\n" ); document.write( "Put the value of y in (1)
\n" ); document.write( "x=y+10
\n" ); document.write( "x=12+10
\n" ); document.write( "x=22\r
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\n" ); document.write( "\n" ); document.write( "Present age of Joe = x = 22 years old
\n" ); document.write( "Present age of James = y = 12 years old\r
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