document.write( "Question 614341: How do I solve:\r
\n" ); document.write( "\n" ); document.write( "7/(2-x) = (10-4x)/(x^2 + 3x - 10)
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Algebra.Com's Answer #386509 by edjones(8007)\"\" \"About 
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7/(2-x) = (10-4x)/(x^2 + 3x - 10)
\n" ); document.write( "7(x^2+3x-10)=(10-4x)(2-x)
\n" ); document.write( "7x^2+21x-70=4x^2-18x+20
\n" ); document.write( "3x^2+39x-90=0
\n" ); document.write( "x^2+13x-30=0
\n" ); document.write( "(x-2)(x+15)=0
\n" ); document.write( "x=-15 The only answer.
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