document.write( "Question 614350: the base of a triangle is 3 meters less then twice the height find the base and the height if the area of a triangle is 22 square meters \n" ); document.write( "
Algebra.Com's Answer #386508 by nerdybill(7384) You can put this solution on YOUR website! the base of a triangle is 3 meters less then twice the height find the base and the height if the area of a triangle is 22 square meters \n" ); document.write( ". \n" ); document.write( "Let x = height \n" ); document.write( "then \n" ); document.write( "2x-3 = base \n" ); document.write( ". \n" ); document.write( "(1/2)(2x-3)x = 22 \n" ); document.write( "(2x-3)x = 44 \n" ); document.write( "2x^2-3x = 44 \n" ); document.write( "2x^2-3x-44=0 \n" ); document.write( "rewrite the middle term as: \n" ); document.write( "2x^2 +8x-11x -44=0 \n" ); document.write( "group terms: \n" ); document.write( "(2x^2+8x)-(11x+44)=0 \n" ); document.write( "2x(x+4)-11(x+4)=0 \n" ); document.write( "(x+4)(2x-11)=0 \n" ); document.write( "x = {-4, 11/2} \n" ); document.write( "throw out the negative solution leaving: \n" ); document.write( "x = 5.5 meters (base) \n" ); document.write( ". \n" ); document.write( "height: \n" ); document.write( "2x-3 = 2(5.5)-3 = 11-3 = 8 meters \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |