document.write( "Question 614312: Solve the system of equations using substitution
\n" ); document.write( "3x + 4y=12
\n" ); document.write( "2x + y=10 \n" ); document.write( "
Algebra.Com's Answer #386485 by mananth(16946)\"\" \"About 
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2 x + 1 y = 10 .............1
\n" ); document.write( "1 y = 10 + -2 x
\n" ); document.write( "/ 1 =
\n" ); document.write( " y = 10 + -2 x
\n" ); document.write( "3 x + 4 y = 12 .....................2
\n" ); document.write( "Substitute y in (2)
\n" ); document.write( "3x+4(10-2x)= 12
\n" ); document.write( "3x+40-8x= 12
\n" ); document.write( "3x-8x =-28
\n" ); document.write( "-5x = -28
\n" ); document.write( "/ -5
\n" ); document.write( "x= 28/ 5
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "2 x + 1 y = 10
\n" ); document.write( "2 * 28/ 5 + 1 y = 10
\n" ); document.write( "11 1/ 5 + 1 y = 10
\n" ); document.write( "1 y = -6/ 5
\n" ); document.write( "/ 1
\n" ); document.write( "y= -6/ 5 \r
\n" ); document.write( "\n" ); document.write( "(28/5 , -6/5)
\n" ); document.write( "m.ananth@hotmail.ca
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