document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56915>Question 56915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a wheel that has 3000 revolutions while rolling in a straight line for 45000 in what is the radius of the wheel </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38648 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if a wheel that has 3000 revolutions while rolling in a straight line for 45000 in what is the radius( R SAY) of the wheel<BR>\n" );
document.write( "PERIMETER OF WHEEL = 2*PI*R = DISTANCE TRAVELLED IN 1 REVOLN.<BR>\n" );
document.write( "DISTANCE TRAVELLED IN 3000 REVOLNS.=3000*2PI*R = 45000<BR>\n" );
document.write( "R = 45000/(3000*2*PI)=7.5/PI = 7.5/3.14= 2.4 APPROX  </SPAN>\n" );
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