document.write( "Question 614106: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100mph and train B is traveling at 120mph. Train A passes a station at 2:20pm and train Bpasses the same train station at 2:32pm. At waht time will train B catch train A \n" ); document.write( "

Algebra.Com's Answer #386478 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Train A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 100mph and train B is traveling at 120mph.
\n" ); document.write( " Train A passes a station at 2:20pm and train B passes the same train station at 2:32pm.
\n" ); document.write( " At what time will train B catch train A
\n" ); document.write( ":
\n" ); document.write( "From the given information, we know that Train B is 12 min behind A at at 2:20 pm
\n" ); document.write( "therefore Train B is:
\n" ); document.write( " $\"12%2F60\"$ * 120 = 24 miles behind Train A at that time.
\n" ); document.write( ":
\n" ); document.write( "Let t = time required for Train B to catch Train A
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Train B dist = Train A dist + 24 mi
\n" ); document.write( "120t = 100t + 24
\n" ); document.write( "120t - 100t = 24
\n" ); document.write( "20t = 24
\n" ); document.write( "t = $\"24%2F20\"$
\n" ); document.write( "t = 1.2 hrs for B to catch A
\n" ); document.write( ":
\n" ); document.write( "Convert 1.2 hrs to hrs and minutes: 1 + .2(60) = 1 hr 12 min
\n" ); document.write( ":
\n" ); document.write( "Find the time from 2:20 pm:
\n" ); document.write( "2:20 + 1:12 = 3:32 pm, Train B catches Train A \n" ); document.write( "

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