document.write( "Question 614010: If a boy travels from home at a spped of 4kms/hr he reaches the school at 10:08 a.m. If he travels at a speed of 5km/hr, he reaches the school at 9:50 a.m. What is the distance from home to school? \n" ); document.write( "

Algebra.Com's Answer #386357 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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If a boy travels from home at a speed of 4kms/hr he reaches the school at 10:08 a.m.
\n" ); document.write( "If he travels at a speed of 5km/hr, he reaches the school at 9:50 a.m.
\n" ); document.write( " What is the distance from home to school?
\n" ); document.write( ":
\n" ); document.write( "From the information given we know that he arrives 18 min earlier when his speed is 5 km/h
\n" ); document.write( "Since we are using km/h, change 18 min to: 18/60 = .3 hrs
\n" ); document.write( ":
\n" ); document.write( "Let d = distance
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "4 km/h time - 5 km/h time = .3 hrs
\n" ); document.write( " $\"d%2F4\"$ - $\"d%2F5\"$ = .3
\n" ); document.write( "multiply by 20 to clear the denominators, results:
\n" ); document.write( "5d - 4d = .3(20)
\n" ); document.write( "d = 6 km is the distance to the school \n" ); document.write( "

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