document.write( "Question 613837: An airplane flying against the wind travels 242 miles in the same time that it can travel 253 miles with the wind. If the wind sped is 15 miles per hour, what is the speed of the airplane in still air ? \n" ); document.write( "
Algebra.Com's Answer #386309 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Plane speed x mph \n" ); document.write( "wind speed 15 mph \n" ); document.write( ".. \n" ); document.write( "against wind x - 15 mph \n" ); document.write( "with wind x + 15 mph \n" ); document.write( " \n" ); document.write( "Distance against wind 242 \n" ); document.write( "Distance with wind 253 \n" ); document.write( "Time = same equate the time against with time with current \n" ); document.write( "t=d/r \n" ); document.write( "242 /(x- 15 )= 253 /(x+ 15 ) \n" ); document.write( "242 *(x+ 15 )= 253 *(x- 15 ) \n" ); document.write( "242 x + 3630 = 253 x -3795 \n" ); document.write( "242 x -253 x = -3795 + -3630 \n" ); document.write( "-11 x = -7425 \n" ); document.write( "/ -11 \n" ); document.write( " x= 675 mph \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |