document.write( "Question 613761: Mr. Gibbs has 3 sons: Joe, John, and Mark. The sums of their ages is equal to the age of their Father. In 1 year, Mr. Gibbs will be twice as old as Joe. In 2 years, Mr. Gibbs will be 3 times as old as John. In 3 years, Mr. Gibbs will be four times as old as Mark. How old is each son now? \n" ); document.write( "
Algebra.Com's Answer #386284 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mr. Gibbs has 3 sons: Joe, John, and Mark. The sums of their ages is equal to the age of their Father. \n" ); document.write( "In 1 year, Mr. Gibbs will be twice as old as Joe. In 2 years, Mr. Gibbs will be 3 times as old as John. \n" ); document.write( " In 3 years, Mr. Gibbs will be four times as old as Mark. How old is each son now? \n" ); document.write( ": \n" ); document.write( "let j = Joe's age \n" ); document.write( "let n = John's age \n" ); document.write( "let m = Mark's age \n" ); document.write( "Let g = father's age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "Mr. Gibbs has 3 sons: Joe, John, and Mark. The sums of their ages is equal to the age of their Father. \n" ); document.write( "j + n + m = g \n" ); document.write( ": \n" ); document.write( "In 1 year, Mr. Gibbs will be twice as old as Joe. \n" ); document.write( "2(j+1) = g + 1 \n" ); document.write( "2j + 2 = g + 1 \n" ); document.write( "2j = g + 1 -2 \n" ); document.write( "2j = g - 1 \n" ); document.write( "j = \n" ); document.write( ": \n" ); document.write( "In 2 years, Mr. Gibbs will be 3 times as old as John. \n" ); document.write( "3(n+2) = g + 2 \n" ); document.write( "3n + 6 = g + 2 \n" ); document.write( "3n = g + 2 - 6 \n" ); document.write( "3n = g - 4 \n" ); document.write( "n = \n" ); document.write( ": \n" ); document.write( "In 3 years, Mr. Gibbs will be four times as old as Mark. \n" ); document.write( "4(m+3) = g + 3 \n" ); document.write( "4m + 12 = g + 3 \n" ); document.write( "4m = g + 3 - 12 \n" ); document.write( "4m = g - 9 \n" ); document.write( "m = \n" ); document.write( ": \n" ); document.write( " How old is each son now? \n" ); document.write( ": \n" ); document.write( "replace j, n, m \n" ); document.write( " \n" ); document.write( "multiply by 12, to get rid of the denominators, results \n" ); document.write( "6(g-1) + 4(g-4) + 3(g-9) = 12g \n" ); document.write( "6g - 6 + 4g - 16 + 3g - 27 = 12g \n" ); document.write( "Combine like terms \n" ); document.write( "6g + 4g + 3g - 6 - 16 - 27 = 12g \n" ); document.write( "13g - 49 = 12g \n" ); document.write( "13g - 12g = 49 \n" ); document.write( "g = 49 yrs is Dad's age \n" ); document.write( ": \n" ); document.write( "Find j \n" ); document.write( "j = \n" ); document.write( "j = 24 yrs is Joe's age \n" ); document.write( "Find n \n" ); document.write( "n = \n" ); document.write( "n = 15 yrs is John's age \n" ); document.write( "Find m \n" ); document.write( "m = \n" ); document.write( "m = 10 yrs is Mark's age \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "see if that works out, \n" ); document.write( "\"The sums of their ages is equal to the age of their Father\" \n" ); document.write( "24 + 15 + 10 = 49 \n" ); document.write( " |