document.write( "Question 56903: CAN SOMEONE PLEASE ASSIST:
\n" ); document.write( "THE LENGTH OF A RECTANGULAR GARDEN IS 8FT LESS THEN 3 TIMES ITS WIDTH. IF THE PERIMETER OF THE GARDEN IS 48FT, FIND THE DIMENSIONS OF THE GARDEN..
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Algebra.Com's Answer #38628 by Scriptor(36)\"\" \"About 
You can put this solution on YOUR website!
Call the length = x
\n" ); document.write( "Call the width = y\r
\n" ); document.write( "\n" ); document.write( "You know that x*y = 48
\n" ); document.write( "You also know that x = 3y - 8\r
\n" ); document.write( "\n" ); document.write( "Substitute this x in x*y=48 to obtain:\r
\n" ); document.write( "\n" ); document.write( "y * (3y-8) = 48\r
\n" ); document.write( "\n" ); document.write( "3y² - 8y - 48 = 0
\n" ); document.write( "Now solve this for y (delete the negative root)
\n" ); document.write( "The rest of the excercise is for you :-)
\n" ); document.write( "(hint: y = 4/3 + 4*sqrt(10)/3 )
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