document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=613807>Question 613807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If log x^2 - log2A= log 3A, then logx expressed in terms of logA is equivalent to....<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #386275 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=386275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If log x^2 - log2A= log 3A, then logx <BR>\n" );
document.write( "expressed in terms of logA is equivalent to....<BR>\n" );
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document.write( "log[x^2/(2A)] = log(3A)<BR>\n" );
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document.write( "x^2/(2A) = (3A)<BR>\n" );
document.write( "x^2 = 6A^2<BR>\n" );
document.write( "x = A*sqrt(6)<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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