document.write( "Question 613731: The height of a triangle is 3 times as long as it's base. If the base is increased by 6cm. and the height is decreased by 5cm. Then the area of the triangle would be 200cm2. What is the height and base of the Original Triangle? \n" ); document.write( "
Algebra.Com's Answer #386252 by lwsshak3(11628)\"\" \"About 
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The height of a triangle is 3 times as long as it's base. If the base is increased by 6cm. and the height is decreased by 5cm. Then the area of the triangle would be 200cm2. What is the height and base of the Original Triangle?
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\n" ); document.write( "let x=base of original triangle
\n" ); document.write( "3x=height of original triangle
\n" ); document.write( "x+6 =base of new triangle
\n" ); document.write( "3x-5=height of new triangle
\n" ); document.write( "area=1/2 base*height
\n" ); document.write( "200=1/2*(x+6)(3x-5)
\n" ); document.write( "(x+6)(3x-5)=400
\n" ); document.write( "x^2+13x-30=400
\n" ); document.write( "3x^2+13x-430=0
\n" ); document.write( "Solve by quadratic formula:
\n" ); document.write( "x=-43/3 (reject, x>0)
\n" ); document.write( "or x=10
\n" ); document.write( "3x=30z
\n" ); document.write( "ans:
\n" ); document.write( "base of original triangle=10 cm
\n" ); document.write( "height of original triangle=30 cm\r
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