document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=613763>Question 613763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! how would you solve something like: lnx+ln2=3, i condensed it down to ln2x=3 and i think that's right, but i'm not sure how to solve for x. Thank you so much!!! My test is tomorrow.\r<BR>\n" );
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document.write( "(ln is the natural log) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #386241 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=386241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x = e^3\r<BR>\n" );
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document.write( "x = e^3 / 2 </SPAN>\n" );
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