document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=613681>Question 613681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4(a-3)=a+30  PLease show me how to solve </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #386156 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=386156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distributing (both the a and the -3 are multiplied by the 4) ___ 4a - 12 = a + 30\r<BR>\n" );
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document.write( "subtracting a and adding 12 ___ 3a = 42\r<BR>\n" );
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document.write( "dividing by 3 ___ a = 14 </SPAN>\n" );
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