document.write( "Question 613676: What percentage of the area of the standard normal distribution is between z = -2.00 and z = +2.00? How do you know this? \n" ); document.write( "

Algebra.Com's Answer #386152 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "What percentage of the area of the standard normal distribution is between z = -2.00 and z = +2.00? 
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document.write( "two standard deviations from the mean account for about 95.45%
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document.write( " P(-2< z <2 ) = NORMSDIST(2) - NORMSDIST(-2) = .97725 - .02275 = .9545 OR 95.45%\r
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