document.write( "Question 613661: find the value of a3+b3+c3-3abc, given that a=2, b=3 and c=-1
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Algebra.Com's Answer #386128 by radh(108)\"\" \"About 
You can put this solution on YOUR website!
All we have to do is substitute what we know in. \"2%283%29%2B3%283%29-1%283%29-3%282%29%283%29%28-1%29\". That might look a little intimidating, but let's take it one step at a time:
\n" ); document.write( "\"6%2B3%283%29-1%283%29-3%282%29%283%29%28-1%29\"
\n" ); document.write( "\"6%2B9-1%283%29-3%282%29%283%29%28-1%29\"
\n" ); document.write( "\"6%2B9-3-3%282%29%283%29%28-1%29\"
\n" ); document.write( "\"6%2B9-3-6%283%29%28-1%29\"
\n" ); document.write( "\"6%2B9-3-18%28-1%29\"
\n" ); document.write( "\"6%2B9-3%2B18\"
\n" ); document.write( "\"15-3%2B18\"
\n" ); document.write( "\"15%2B15\"
\n" ); document.write( "\"30\"\r
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Your final answer is 30. :) \n" ); document.write( "

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