document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=613476>Question 613476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three consecutive multiples of 5 is 90. find the numbers. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #386111 by </B><A HREF=/tutors/aboutme.mpl?userid=Charles1947><B>Charles1947(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Charles1947><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=386111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of three consecutive multiples of 5 is 90. find the numbers. \r<BR>\n" );
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document.write( "Let the first number be x.\r<BR>\n" );
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document.write( "The next number is x+5.\r<BR>\n" );
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document.write( "The next number is x+10.\r<BR>\n" );
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document.write( "x+(x+5)+(x+10)=90\r<BR>\n" );
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document.write( "x+x+5+x+10=90\r<BR>\n" );
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document.write( "combine terms\r<BR>\n" );
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document.write( "3x+15+90\r<BR>\n" );
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document.write( "Subtract 15 from both sides of the equation.\r<BR>\n" );
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document.write( "3x=75\r<BR>\n" );
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document.write( "Divide both sides of the equation by 3\r<BR>\n" );
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document.write( "x=25, x+5=30, x+10=35\r<BR>\n" );
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document.write( "Check  25+30+35=90 </SPAN>\n" );
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