document.write( "Question 56851: Find three consecutive odd integers such that the sum of the smallest and 4 times the largest is 61. \n" ); document.write( "
Algebra.Com's Answer #38610 by Scriptor(36)\"\" \"About 
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Call your first odd number 2n+1 , the second one 2n+3 and the last one 2n+5\r
\n" ); document.write( "\n" ); document.write( "Since the sum of the smallest and 4 times the largest is 61, we get that:\r
\n" ); document.write( "\n" ); document.write( "(2n+1) + 4(2n+5) = 61\r
\n" ); document.write( "\n" ); document.write( "2n + 1 + 8n + 20 = 61\r
\n" ); document.write( "\n" ); document.write( "10n = 40\r
\n" ); document.write( "\n" ); document.write( "n =4 => 2n+1 = 9\r
\n" ); document.write( "\n" ); document.write( "Answer: 9,11,13\r
\n" ); document.write( "\n" ); document.write( "Note: we could have solved it with x instead of 2n+1, but I wanted to show clear that it is an odd number.
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