document.write( "Question 56864: 1) Solve the following equations.\r
\n" ); document.write( "\n" ); document.write( "a) sqrt x -2=1
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\n" ); document.write( "\n" ); document.write( "b) sqrt x³ =27
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\n" ); document.write( "\n" ); document.write( "c) 3sqrt x2 =9
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Algebra.Com's Answer #38609 by Scriptor(36)\"\" \"About 
You can put this solution on YOUR website!
a) \"sqrt%28x-2%29=1\"\r
\n" ); document.write( "\n" ); document.write( " Now multiply at both sides to obtain:\r
\n" ); document.write( "\n" ); document.write( " \"%28sqrt%28x-2%29%29%5E2=1%5E2\"\r
\n" ); document.write( "\n" ); document.write( "This means that x-2 = 1, so x = 3\r
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\n" ); document.write( "\n" ); document.write( "b) The only x that satisfies is x=3, try it!\r
\n" ); document.write( "\n" ); document.write( "c)\"9=3%2Asqrt%28x%5E2%29=3%2Ax\"\r
\n" ); document.write( "\n" ); document.write( " So 3*x = 9 => x=3
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