document.write( "Question 613570: The half-life of tritium is 12.4 years. How long will it take for 20% of a sample of tritium to decompose?
\n" ); document.write( "Please round the answer to the nearest tenth. \r
\n" ); document.write( "\n" ); document.write( "-log5= -t/12.4 log2 --> 12.4(log5\log2)=t --> t=28.8
\n" ); document.write( "I know this is incorrect
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Algebra.Com's Answer #386073 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
N = P*e^(-kt)\r
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\n" ); document.write( "\n" ); document.write( "1/2P = P*e^(-k*12.4)\r
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\n" ); document.write( "\n" ); document.write( "1/2 = e^(-12.4k)\r
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\n" ); document.write( "\n" ); document.write( "ln(1/2) = -12.4k\r
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\n" ); document.write( "\n" ); document.write( "-0.693147 = -12.4k\r
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\n" ); document.write( "\n" ); document.write( "-0.693147/(-12.4) = k\r
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\n" ); document.write( "\n" ); document.write( "0.05589895 = k\r
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\n" ); document.write( "\n" ); document.write( "k = 0.05589895\r
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\n" ); document.write( "\n" ); document.write( "N = P*e^(-kt)\r
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\n" ); document.write( "\n" ); document.write( "N = P*e^(-0.05589895t)\r
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\n" ); document.write( "\n" ); document.write( "0.8P = P*e^(-0.05589895t)\r
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\n" ); document.write( "\n" ); document.write( "0.8 = e^(-0.05589895t)\r
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\n" ); document.write( "\n" ); document.write( "ln(0.8) = -0.05589895t\r
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\n" ); document.write( "\n" ); document.write( "-0.22314355 = -0.05589895t\r
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\n" ); document.write( "\n" ); document.write( "-0.22314355/(-0.05589895) = t\r
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\n" ); document.write( "\n" ); document.write( "3.9919095 = t\r
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\n" ); document.write( "\n" ); document.write( "t = 3.9919095\r
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\n" ); document.write( "\n" ); document.write( "So it will take roughly 3.9919095 years for 20% of the sample to decompose.
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