document.write( "Question 613389: A high school track coach determines that his fastest long distance runner runs 2 miles per hour faster than his slowest runner. Compared to the faster runner, the slower runner takes a half hour longer to run 12 miles.\r
\n" ); document.write( "\n" ); document.write( "a. Find the average rates of both runners.
\n" ); document.write( "b. Find the time for both runners to run 12 miles.
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Algebra.Com's Answer #386041 by ankor@dixie-net.com(22740)\"\" \"About 
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A high school track coach determines that his fastest long distance runner runs 2 miles per hour faster than his slowest runner.
\n" ); document.write( " Compared to the faster runner, the slower runner takes a half hour longer to run 12 miles.
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\n" ); document.write( "a. Find the average rates of both runners.
\n" ); document.write( "Let s = speed of the slower runner
\n" ); document.write( "then
\n" ); document.write( "(s+2) = speed of the faster runner
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\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "\"12%2Fs\" - \"12%2F%28%28s%2B2%29%29\" = .5 hr
\n" ); document.write( "Multiply s(s+2), results:
\n" ); document.write( "12(s+2) - 12s = .5s(s+2)
\n" ); document.write( "12s + 24 - 12s = .5s^2 + s
\n" ); document.write( "0 = .5s^2 + s - 24
\n" ); document.write( "multiply by 2, to get rid of the decimal
\n" ); document.write( "s^2 + 2s - 48 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(s+8)(s-6) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "s = 6 mph the slow runner
\n" ); document.write( "then
\n" ); document.write( "6 + 2 = 8 mph is the faster runner
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\n" ); document.write( "b. Find the time for both runners to run 12 miles.
\n" ); document.write( "12/8 = 1.5 hrs the faster runner
\n" ); document.write( "12/6 = 2 hrs the slower\r
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