document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56859>Question 56859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8xy2/12x3y5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38603 by </B><A HREF=/tutors/aboutme.mpl?userid=BGluvsmath><B>BGluvsmath(64)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BGluvsmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8xy^2/12x^3y^5<BR>\n" );
document.write( "8/12 reduces to 2/3<BR>\n" );
document.write( "x/x^3 simplifies to 1/x^2<BR>\n" );
document.write( "y^2/y^5 simplifies to 1/y^3<BR>\n" );
document.write( "Therefore, 8xy^2/12x^3y^5 simplifies to 2/3x^2y^3.  Note that it is important to keep the variables in the denominator; otherwise, the exponents become negative. </SPAN>\n" );
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