document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=613364>Question 613364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Darlene built a small triangular patio on the back of her house.<BR>\n" );
document.write( "The length of each of the equal and perpendicular sides of the patio is represented by the letter x. The longest side of the patio is 16 feet.  What is the approximate measure , in feet, of x?  \r<BR>\n" );
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document.write( "The answer is 11.3. I feel I need to use the pythagorian to solve, but I am comming up with x^2+x^2=256, and get lost there.  help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #386014 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=386014\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You're on the right track\r<BR>\n" );
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document.write( "a^2+b^2 = c^2\r<BR>\n" );
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document.write( "x^2+x^2 = 16^2\r<BR>\n" );
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document.write( "x^2+x^2 = 256\r<BR>\n" );
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document.write( "2x^2 = 256\r<BR>\n" );
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document.write( "x^2 = 256/2\r<BR>\n" );
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document.write( "x^2 = 128\r<BR>\n" );
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document.write( "x = sqrt(128)\r<BR>\n" );
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document.write( "x = sqrt(64*2)\r<BR>\n" );
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document.write( "x = sqrt(64)*sqrt(2)\r<BR>\n" );
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document.write( "x = 8*sqrt(2)\r<BR>\n" );
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document.write( "x = 8*1.41421356\r<BR>\n" );
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document.write( "x = 11.313708\r<BR>\n" );
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document.write( "Round this to the nearest tenth to get x = 11.3 </SPAN>\n" );
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