document.write( "Question 613356: Factor the polynomial expression. If necessary, use the caret (^) to enter exponents. For example, write x2 as x^2.6x^2 + 5x - 4 \n" ); document.write( "
Algebra.Com's Answer #385993 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"6x%5E2%2B5x-4\", we can see that the first coefficient is \"6\", the second coefficient is \"5\", and the last term is \"-4\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"6\" by the last term \"-4\" to get \"%286%29%28-4%29=-24\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-24\" (the previous product) and add to the second coefficient \"5\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-24\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-24\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,8,12,24\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-8,-12,-24\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-24\".\r
\n" ); document.write( "\n" ); document.write( "1*(-24) = -24
\n" ); document.write( "2*(-12) = -24
\n" ); document.write( "3*(-8) = -24
\n" ); document.write( "4*(-6) = -24
\n" ); document.write( "(-1)*(24) = -24
\n" ); document.write( "(-2)*(12) = -24
\n" ); document.write( "(-3)*(8) = -24
\n" ); document.write( "(-4)*(6) = -24\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"5\":\r
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First NumberSecond NumberSum
1-241+(-24)=-23
2-122+(-12)=-10
3-83+(-8)=-5
4-64+(-6)=-2
-124-1+24=23
-212-2+12=10
-38-3+8=5
-46-4+6=2
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-3\" and \"8\" add to \"5\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-3\" and \"8\" both multiply to \"-24\" and add to \"5\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"5x\" with \"-3x%2B8x\". Remember, \"-3\" and \"8\" add to \"5\". So this shows us that \"-3x%2B8x=5x\".\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2Bhighlight%28-3x%2B8x%29-4\" Replace the second term \"5x\" with \"-3x%2B8x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%286x%5E2-3x%29%2B%288x-4%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%282x-1%29%2B%288x-4%29\" Factor out the GCF \"3x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%282x-1%29%2B4%282x-1%29\" Factor out \"4\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%2B4%29%282x-1%29\" Combine like terms. Or factor out the common term \"2x-1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"6x%5E2%2B5x-4\" factors to \"%283x%2B4%29%282x-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"6x%5E2%2B5x-4=%283x%2B4%29%282x-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%283x%2B4%29%282x-1%29\" to get \"6x%5E2%2B5x-4\" or by graphing the original expression and the answer (the two graphs should be identical).
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