document.write( "Question 613345: 1. 2^(5-3x)=1/16 how you do this and whats the answer\r
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\n" ); document.write( "\n" ); document.write( "3. 9^2x(27^(3+x))=1/9 how you do this and whats the answer\r
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Algebra.Com's Answer #385989 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi, 
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document.write( "      5-3x = -4
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document.write( "        9 = 3x
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document.write( "         3 = x
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document.write( "log6x+log6(x-3)=2
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document.write( "log6(x(x-3)) =2
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document.write( " 6^2 = x(x-3) 
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document.write( "  x^2 -3x -36 = 0
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document.write( "  (x-12)(x+3) = 0
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document.write( "    x = 12  Thowing out negative solution for log6(x)\r
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