document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=613288>Question 613288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a person plans to invest twice as much in an account that pays 8% annual interest as in an account that pays 13% annual interest. how much will the person have to invest in each account to earn a total of 1885 in one year </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385984 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385984\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the amount to be invested at 13% and 2x = the amount to be invested at 8%.<BR>\n" );
document.write( "The sum of the interests earned on these two amounts can be expressed as:<BR>\n" );
document.write( "x(0.13)+2x(0.08) and this is to equal 1885 per annum, so you can write the equation needed to solve for x:<BR>\n" );
document.write( "0.13x+0.16x = 1885 Simplify.<BR>\n" );
document.write( "0.29x = 1885 Divide both sides by 0.29<BR>\n" );
document.write( "x = 6,500 and 2x = 13,000<BR>\n" );
document.write( "The person would need to invest 6,500 at 13% and 13,000 at 8% in order to earn 1,885 per annum.<BR>\n" );
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