document.write( "Question 613306: Suppose the diameter of a circle is 26 ft. long and a chord is 10 ft. long. Find the distance from the center of the circle to the chord. Show your work.
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Algebra.Com's Answer #385941 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Draw out a picture to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: the diameter is 26, so the radius is 26/2 = 13. Also, the chord is bisected by the diameter, which allows us to cut that chord of 10 in half to get 2 pieces of 5.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we can see we have a right triangle. Let's use the pythagorean theorem to solve for x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a^2+b^2 = c^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5^2+x^2 = 13^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25+x^2 = 169\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 = 169-25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 = 144\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = sqrt(144)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the distance from the center to the chord is 12 feet. \n" ); document.write( " |