document.write( "Question 613306: Suppose the diameter of a circle is 26 ft. long and a chord is 10 ft. long. Find the distance from the center of the circle to the chord. Show your work.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #385941 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Draw out a picture to get\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Note: the diameter is 26, so the radius is 26/2 = 13. Also, the chord is bisected by the diameter, which allows us to cut that chord of 10 in half to get 2 pieces of 5.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So we can see we have a right triangle. Let's use the pythagorean theorem to solve for x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a^2+b^2 = c^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5^2+x^2 = 13^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "25+x^2 = 169\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x^2 = 169-25\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x^2 = 144\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = sqrt(144)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 12\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the distance from the center to the chord is 12 feet.
\n" ); document.write( "
\n" );