document.write( "Question 613244: A ball is thrown off the top of a classroom building with an initial upward velocity of 10 feet per second. The height above the ground can be found using h= -16t(squared) + 10t + 40 with t representing time in seconds and h representing height in feet. How high is the ball after 0.8 seconds? When will the ball be 20 feet above the ground and headed down? \n" ); document.write( "
Algebra.Com's Answer #385906 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A ball is thrown off the top of a classroom building with an initial upward velocity of 10 feet per second. The height above the ground can be found using h= -16t(squared) + 10t + 40 with t representing time in seconds and h representing height in feet. How high is the ball after 0.8 seconds? \n" ); document.write( "----- \n" ); document.write( "Sub 0.8 for t \n" ); document.write( "h(0.8) = -16*0.8^2 + 10*0.8 + 40 \n" ); document.write( "= 37.76 feet \n" ); document.write( "----------------- \n" ); document.write( "When will the ball be 20 feet above the ground and headed down? \n" ); document.write( "h = 20 \n" ); document.write( "20 = -16t^2 + 10t + 40 \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "======================= \n" ); document.write( "Ignore the negative solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |