document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=362457>Question 362457</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1).a set of 50 data values has a mean of 40 and a variance of 25. \r<BR>\n" );
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document.write( "a). Find the standard score (z) for a data value = 47. \r<BR>\n" );
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document.write( "b). Find the probability of a data value >47.\r<BR>\n" );
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document.write( "(2). Find the area under the standard normal curve:\r<BR>\n" );
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document.write( "I. to the right of z = 1.83<BR>\n" );
document.write( "II. to the left of z = 1.83 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385883 by </B><A HREF=/tutors/aboutme.mpl?userid=sunsetatdawn><B>sunsetatdawn(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sunsetatdawn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sunsetatdawn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The answer to #1 I don't think is quite right. We are supposed to divide by standard deviation, not variance. To get this, find the square root of the variance. <BR>\n" );
document.write( "so it is more like this (47 - 40)/sqrt25 = 7/5 = 1.4 </SPAN>\n" );
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