document.write( "Question 613103: Bacteria are growing exponentially in an environment of unlimited space and food. The doubling time is 1 hour.\r
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document.write( "a) If there are initially x milligrams of bacteria, express the mass of the bacteria as a function of time t.
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document.write( "f(t)=\r
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document.write( "b) Use your answer to (a) to write down an equation whose solution is the time at which there are 3x milligrams of bacteria. Enter your answer in the form, eg . \r
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document.write( "c) Solve your equation from (b)
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document.write( "t = hours
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document.write( "d) Your answer to (c) should be between 1 and 2 hours. Check that it is. Do you understand why it has to be ? \n" );
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Algebra.Com's Answer #385876 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Bacteria are growing exponentially in an environment of unlimited space and food. The doubling time is 1 hour. \n" ); document.write( "a) If there are initially x milligrams of bacteria, express the mass of the bacteria as a function of time t. \n" ); document.write( "f(t)=x*2^t \n" ); document.write( "------------- \n" ); document.write( "b) Use your answer to (a) to write down an equation whose solution is the time at which there are 3x milligrams of bacteria. Enter your answer in the form, \n" ); document.write( "3x = x*2^t \n" ); document.write( "2^t = 3 \n" ); document.write( "t = ln(3)/ln(2) = 1.585 hrs \n" ); document.write( "-------------------------------- \n" ); document.write( " . \n" ); document.write( "c) Solve your equation from (b) \n" ); document.write( "t = 1.585 hours \n" ); document.write( "------------------------- \n" ); document.write( "d) Your answer to (c) should be between 1 and 2 hours. Check that it is. Do you understand why it has to be ? \n" ); document.write( "The quantity is 2x after 1 hr. \n" ); document.write( "The quantity is 4x after 2 hrs. \n" ); document.write( "Since the quantity is 3x the time must be between 1 and 2 hours. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " \n" ); document.write( " |