document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=613049>Question 613049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write a rule for thrnth term of the arithmetic sequence....\r<BR>\n" );
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document.write( "  a6=-31,a14=-135 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385861 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are 8 terms from a6 to a14; the difference is -104 (-135 - -31)<BR>\n" );
document.write( "___ so the common difference between two consecutive terms is -13 (-104 / 8)\r<BR>\n" );
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document.write( "an = -13n + ?\r<BR>\n" );
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document.write( "substitute to find the \"fudge factor\" ___ a6 = -13(6) + ? ___ -31 = -78 + ? ___ 47 = ?\r<BR>\n" );
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document.write( "an = -13n + 47 </SPAN>\n" );
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