document.write( "Question 613046: 14x^3 + 21x^2 + 16x + 24\r
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Algebra.Com's Answer #385857 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you want to factor this.\r
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\n" ); document.write( "\n" ); document.write( "\"14x%5E3%2B21x%5E2%2B16x%2B24\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%2814x%5E3%2B21x%5E2%29%2B%2816x%2B24%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"7x%5E2%282x%2B3%29%2B8%282x%2B3%29\" Factor out the GCF \"7x%5E2\" out of the first group. Factor out the GCF \"8\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%287x%5E2%2B8%29%282x%2B3%29\" Since we have the common term \"2x%2B3\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"14x%5E3%2B21x%5E2%2B16x%2B24\" factors to \"%287x%5E2%2B8%29%282x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"14x%5E3%2B21x%5E2%2B16x%2B24=%287x%5E2%2B8%29%282x%2B3%29\"
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