document.write( "Question 612982: The area of a rectangle is 96 square centimeters. If the width of the rectangle is 4 centimeters less than its length, what are the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #385839 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
\n" );
document.write( "Hi, 
\n" );
document.write( " width of the rectangle is 4 centimeters less than its length
\n" );
document.write( "Let x and (x-4) represent length and width respectively
\n" );
document.write( "Question states***
\n" );
document.write( "x(x-4)= 96 in^2
\n" );
document.write( " x^2 - 4x - 96 = 0
\n" );
document.write( " (x-12)(x+8) = 0
\n" );
document.write( "    x = 12, throwing out negative solution for unit measure
\n" );
document.write( " Length is 12cm and width is 8cm
\n" );
document.write( "   12in*8in = 96cm^2 \n" );
document.write( "

\n" );