document.write( "Question 612956: 5y sqrt(8y)+2 sqrt(50y^3) \n" ); document.write( "

Algebra.Com's Answer #385838 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"5y%2Asqrt%288y%29%2B2%2Asqrt%2850y%5E3%29\"$
\n" ); document.write( "The two terms, as they stand, are not like terms so we cannot add them together. But both square roots have perfect square factors so we can simplify each one:
\n" ); document.write( " $\"5y%2Asqrt%284%2A2y%29%2B2%2Asqrt%2825%2Ay%5E2%2A2y%29\"$
\n" ); document.write( " $\"5y%2Asqrt%284%29%2Asqrt%282y%29%2B2%2Asqrt%2825%29%2Asqrt%28y%5E2%29%2Asqrt%282y%29\"$
\n" ); document.write( " $\"5y%2A2%2Asqrt%282y%29%2B2%2A5%2Ay%2Asqrt%282y%29\"$
\n" ); document.write( "Note: Because the initial square roots had odd powers of y, we know that y cannot be negative. So an absolute value is not necessary around the \"y\" we got from $\"sqrt%28y%5E2%29\"$ .
\n" ); document.write( "Continuing to simplify...
\n" ); document.write( " $\"10y%2Asqrt%282y%29%2B10y%2Asqrt%282y%29\"$

\n" ); document.write( "Now that the square roots are simplified, we happen to have like terms that can be added together! (Note: This does not always happen.) Adding the terms together we get:
\n" ); document.write( " $\"20y%2Asqrt%282y%29\"$ \n" ); document.write( "

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