document.write( "Question 612974: May you please help me solve this logarithm -log2-x=-2 \n" ); document.write( "
Algebra.Com's Answer #385829 by Earlsdon(6294)\"\" \"About 
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Solve for x:
\n" ); document.write( "\"-Log%282-x%29+=+-2\" Multiply both sides by -1.
\n" ); document.write( "\"Log%282-x%29+=+2\" Rewrite this in exponential form: \"Log%5Bb%5D%28x%29+=+y\"--->\"b%5Ey+=+x\"
\n" ); document.write( "\"10%5E2+=+2-x\" Subtract 2 from both sides.
\n" ); document.write( "\"100-2+=+-x\" Simplify:
\n" ); document.write( "\"x+=+-98\"
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