document.write( "Question 612944: I'm trying to teach myself logarithms and I am having trouble with this problem and would really appreciate it if you could help:\r
\n" ); document.write( "\n" ); document.write( "\"+log+%28+e+%2C+x-2+%29+=+3+\"\r
\n" ); document.write( "\n" ); document.write( "Just in case I didn't enter that right, the problem is: The natural logarithm of (x-2) = 3 and I need to solve for x. I have tried changing the problem into log ( e , x ) / log ( e , -2 ) = 3(log ( e , -2 ) but I'm pretty sure that's wrong. I don't really know what to do. Thanks.
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Algebra.Com's Answer #385810 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To make things shorter, we can say \"ln%28x-2%29\" since ln (lowercase L then n) is the natural logarithm (ie log base 'e')\r
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\n" ); document.write( "\n" ); document.write( "So we can say \"ln%28x-2%29+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28x-2%29+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-2+=+e%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+e%5E3%2B2\"
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