document.write( "Question 612938: Factor By Grouping\r
\n" ); document.write( "\n" ); document.write( "2x^2+6xy-5xy-15y^2\r
\n" ); document.write( "\n" ); document.write( "Please show and explain steps on how to factor this by grouping. Thanks so much!
\n" ); document.write( "

Algebra.Com's Answer #385804 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B6xy-5xy-15y%5E2\" Start with the given expression\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282x%5E2%2B6xy%29%2B%28-5xy-15y%5E2%29\" Group the terms in two pairs\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x%28x%2B3y%29-5y%28x%2B3y%29\" Factor out the GCF \"2x\" out of the first group. Factor out the GCF \"-5y\" out of the second group\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282x-5y%29%28x%2B3y%29\" Since we have the common term \"x%2B3y\", we can combine like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B6xy-5xy-15y%5E2\" factors to \"%282x-5y%29%28x%2B3y%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words, \"2x%5E2%2B6xy-5xy-15y%5E2=%282x-5y%29%28x%2B3y%29\" for all values of x and y.
\n" ); document.write( "
\n" );