document.write( "Question 612880: Solve using the substitution method:
\n" ); document.write( "r=-3s
\n" ); document.write( "r+4s=10
\n" ); document.write( "and please explain
\n" ); document.write( "

Algebra.Com's Answer #385802 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Solve using the substitution method:
\n" ); document.write( ":
\n" ); document.write( "r = -3s; use this for substitution in the 2nd equation
\n" ); document.write( ":
\n" ); document.write( "r + 4s = 10
\n" ); document.write( "substitute -3s for r, then solve for s
\n" ); document.write( "-3s + 4s = 10
\n" ); document.write( "s = 10
\n" ); document.write( "find r using the 1st equation
\n" ); document.write( "r = -3s
\n" ); document.write( "substitute 10 for s
\n" ); document.write( "r = -3(10)
\n" ); document.write( "r = -30
\n" ); document.write( ":
\n" ); document.write( "The solutions: r = -30, s = 10
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this in the 2nd equation
\n" ); document.write( "r + 4s = 10
\n" ); document.write( "substitute for r and s
\n" ); document.write( "-30 + 4(10) =
\n" ); document.write( "-30 + 40 = 10; confirms our solutions
\n" ); document.write( "
\n" );