document.write( "Question 612880: Solve using the substitution method:
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document.write( "r=-3s
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document.write( "r+4s=10
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document.write( "and please explain \n" );
document.write( "
Algebra.Com's Answer #385802 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve using the substitution method: \n" ); document.write( ": \n" ); document.write( "r = -3s; use this for substitution in the 2nd equation \n" ); document.write( ": \n" ); document.write( "r + 4s = 10 \n" ); document.write( "substitute -3s for r, then solve for s \n" ); document.write( "-3s + 4s = 10 \n" ); document.write( "s = 10 \n" ); document.write( "find r using the 1st equation \n" ); document.write( "r = -3s \n" ); document.write( "substitute 10 for s \n" ); document.write( "r = -3(10) \n" ); document.write( "r = -30 \n" ); document.write( ": \n" ); document.write( "The solutions: r = -30, s = 10 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this in the 2nd equation \n" ); document.write( "r + 4s = 10 \n" ); document.write( "substitute for r and s \n" ); document.write( "-30 + 4(10) = \n" ); document.write( "-30 + 40 = 10; confirms our solutions \n" ); document.write( " |