document.write( "Question 612855: IF JOSEPH CAN ENCODE ONE BOX FILE OF DATA WITHIN 4 HOURS, AND JOEL CAN ENCODE THE SAME VOLUME(1 BOX FILE) WITHIN 7 HOURS, HOW LONG CAN THEY FINISH 150 BOX FILES TOGETHER? \n" ); document.write( "
Algebra.Com's Answer #385753 by stanbon(75887)\"\" \"About 
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IF JOSEPH CAN ENCODE ONE BOX FILE OF DATA WITHIN 4 HOURS, AND JOEL CAN ENCODE THE SAME VOLUME(1 BOX FILE) WITHIN 7 HOURS, HOW LONG CAN THEY FINISH 150 BOX FILES TOGETHER?
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\n" ); document.write( "Joseph rate: 1/4 box/hr
\n" ); document.write( "Joel rate:: 1/7 box/hr
\n" ); document.write( "Together rate: 1/x box/hr
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/4 + 1/7 = 1/x
\n" ); document.write( "7x + 4x = 28
\n" ); document.write( "11x = 28
\n" ); document.write( "x = 28/11 boxes (# of hrs to complete one box together)
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\n" ); document.write( "# of hrs to complete 150 boxes = 150/(28/11) = 150*11/28 = 58.93 hrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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