document.write( "Question 612855: IF JOSEPH CAN ENCODE ONE BOX FILE OF DATA WITHIN 4 HOURS, AND JOEL CAN ENCODE THE SAME VOLUME(1 BOX FILE) WITHIN 7 HOURS, HOW LONG CAN THEY FINISH 150 BOX FILES TOGETHER? \n" ); document.write( "
Algebra.Com's Answer #385753 by stanbon(75887) ![]() You can put this solution on YOUR website! IF JOSEPH CAN ENCODE ONE BOX FILE OF DATA WITHIN 4 HOURS, AND JOEL CAN ENCODE THE SAME VOLUME(1 BOX FILE) WITHIN 7 HOURS, HOW LONG CAN THEY FINISH 150 BOX FILES TOGETHER? \n" ); document.write( "--------- \n" ); document.write( "Joseph rate: 1/4 box/hr \n" ); document.write( "Joel rate:: 1/7 box/hr \n" ); document.write( "Together rate: 1/x box/hr \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/4 + 1/7 = 1/x \n" ); document.write( "7x + 4x = 28 \n" ); document.write( "11x = 28 \n" ); document.write( "x = 28/11 boxes (# of hrs to complete one box together) \n" ); document.write( "======================= \n" ); document.write( "# of hrs to complete 150 boxes = 150/(28/11) = 150*11/28 = 58.93 hrs \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |