document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=56829>Question 56829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am struggling with this word problem, I would like some help on how to complete these type of problems. Here is the problem: If 4 times an interger is increased by 3, the result is between 13 and 25. What is the interger? Please help me. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #38574 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=38574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4x+3)>=13 & <=25<BR>\n" );
document.write( "4x+3=13<BR>\n" );
document.write( "4x=13-3<BR>\n" );
document.write( "4x=10<BR>\n" );
document.write( "x=10/4<BR>\n" );
document.write( "x=2.5 (3)<BR>\n" );
document.write( "4x+3=25<BR>\n" );
document.write( "4x=25-3<BR>\n" );
document.write( "4x=22<BR>\n" );
document.write( "x=22/4<BR>\n" );
document.write( "x=5.5 (5)<BR>\n" );
document.write( "therefore the unknown number is 3,4 or 5<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "4*3+3=12+3=15<BR>\n" );
document.write( "4*4+3=16+3=19<BR>\n" );
document.write( "4*5+3=20+3=23<BR>\n" );
document.write( "all solution are intergers that satisfy the equation 3x+3>=13 & <=25.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );