document.write( "Question 612835: In 1993, the life expency of males in a certain country was 62.7 years. In 2000 it was 65.5 years. what will the life expency be in 2009? \n" ); document.write( "
Algebra.Com's Answer #385738 by stanbon(75887) ![]() You can put this solution on YOUR website! In 1993, the life expectancy of males in a certain country was 62.7 years. In 2000 it was 65.5 years. what will the life expectanncy be in 2009? \n" ); document.write( "----- \n" ); document.write( "You have 2 points:(0,62.7) and (7,65.5) where the x-value is \n" ); document.write( "# of years after 1993. \n" ); document.write( "----- \n" ); document.write( "slope = (65.5-63.7)/7 = 0.2571 \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "life exect = 0.2571(yrs after 1993) + 62.7 \n" ); document.write( "----------------------- \n" ); document.write( "le = 0.2571(16) + 62.7 \n" ); document.write( "le = 66.81 yrs \n" ); document.write( "==================== \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |