document.write( "Question 612774: How many gallons of an 80% alcohol solution must be mixed with 50 gallons of a 16% solution to obtain a solution that is 70% alcohol \n" ); document.write( "
Algebra.Com's Answer #385712 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many gallons of an 80% alcohol solution must be mixed with 50 gallons of a 16% solution to obtain a solution that is 70% alcohol \n" ); document.write( "-------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.80x + 0.16*50 = 0.70(x+50) \n" ); document.write( "80x + 16*50 = 70x + 70*50 \n" ); document.write( "10x = 54*50 \n" ); document.write( "x = 5*54 \n" ); document.write( "x = 270 gallons (amt. of 80% solution needed) \n" ); document.write( "================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |