document.write( "Question 612774: How many gallons of an 80% alcohol solution must be mixed with 50 gallons of a 16% solution to obtain a solution that is 70% alcohol \n" ); document.write( "
Algebra.Com's Answer #385712 by stanbon(75887)\"\" \"About 
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How many gallons of an 80% alcohol solution must be mixed with 50 gallons of a 16% solution to obtain a solution that is 70% alcohol
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.80x + 0.16*50 = 0.70(x+50)
\n" ); document.write( "80x + 16*50 = 70x + 70*50
\n" ); document.write( "10x = 54*50
\n" ); document.write( "x = 5*54
\n" ); document.write( "x = 270 gallons (amt. of 80% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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