document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=612620>Question 612620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of a 2 digit number and number formed by reversing the digits is 88 if the digits differ by 2. find the no.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385696 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two ways to do it:\r<BR>\n" );
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document.write( "Let the number be 10a+b, where a and b are digits. The \"reversed\" number is 10b+a, and \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE (10a+b) + (10b+a) = 88 \Rightarrow 11(a+b) = 88 \Rightarrow a+b = 8\">\r<BR>\n" );
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document.write( "Therefore 17,26,35,44,53,62,71 are the only possible integers. 35 and 53 are the only ones that differ by two, so the answer is {35,53}.\r<BR>\n" );
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document.write( "The other way to do it is let the number be 10a + (a+2); switching the digits gives 10(a+2) + a. Do the same method as shown above. </SPAN>\n" );
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