document.write( "Question 612723: I am very confused by the problem below, mostly once you get the common denominator. What do you do after you get that to complete the problem? We were shown an example, but it was not very explanatory. Any helpful tips would be much appreciated. Thanks!!!
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\n" ); document.write( "During the first part of a trip, a canoeist travels 49 miles at a certain speed. The canoeist travels 4 miles on the second part of the trip at a speed of 5 mph slower. The total time for the trip is 2 hours. What was the speed on each part of the trip?
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Algebra.Com's Answer #385695 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
During the first part of a trip, a canoeist travels 49 miles at a certain speed.
\n" ); document.write( " The canoeist travels 4 miles on the second part of the trip at a speed of 5 mph slower.
\n" ); document.write( " The total time for the trip is 2 hours.
\n" ); document.write( " What was the speed on each part of the trip?
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\n" ); document.write( "Let s = speed on the 1st 49 mi
\n" ); document.write( "then
\n" ); document.write( "(s-5) = speed on the 2nd part (4 mi)
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\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "\"49%2Fs\" + \"4%2F%28%28s-5%29%29\" = 2
\n" ); document.write( "Multiply by s(s-5)
\n" ); document.write( "s(s-5)*\"49%2Fs\" + s(s-5)*\"4%2F%28%28s-5%29%29\" = 2s(s-5)
\n" ); document.write( "Cancel the denominators
\n" ); document.write( "49(s-5) + 4s = 2s^2 - 10s
\n" ); document.write( "49s - 245 + 4s = 2s^2 - 10s
\n" ); document.write( "53s - 245 = 2s^2 - 10s
\n" ); document.write( "Combine as a quadratic equation on the right
\n" ); document.write( "0 = 2s^2 - 10s - 53s + 245
\n" ); document.write( "2s^2 - 63s + 245 = 0
\n" ); document.write( "We have to use the quadratic formula to find s
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this problem; x=s; a=2; b=-63; c= 245
\n" ); document.write( "\"s+=+%28-%28-63%29+%2B-+sqrt%28-63%5E2-4%2A2%2A245+%29%29%2F%282%2A2%29+\"
\n" ); document.write( "Two solutions, but only one will make sense
\n" ); document.write( "s ~ 26.955 mi for the 1st 49 mi
\n" ); document.write( "then
\n" ); document.write( "26.955 - 5 = 21.955 mph for the last 4 mi
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\n" ); document.write( "Confirm this; find the time with these solutions
\n" ); document.write( "\"49%2F26.955\" + \"4%2F20.955\" = 2
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