document.write( "Question 612703: Car A leaves Santa Barbara at noon traveling south toward Los Angeles at 70 mph. At 1pm car B leaves Los Angeles traveling north toward Santa Barbara at 90 mph. The distance between the cars at noon was 100 miles. If car B does not get pulled over, how many minutes after car B leaves will they pass each other? \n" ); document.write( "

Algebra.Com's Answer #385685 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Car A leaves Santa Barbara at noon traveling south toward Los Angeles at 70 mph.
\n" ); document.write( " At 1pm car B leaves Los Angeles traveling north toward Santa Barbara at 90 mph.
\n" ); document.write( " The distance between the cars at noon was 100 miles.
\n" ); document.write( " If car B does not get pulled over, how many minutes after car B leaves will they pass each other?
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time of Car B
\n" ); document.write( "then
\n" ); document.write( "(t+1) = travel time of Car A
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "90t + 70(t+1) = 100
\n" ); document.write( "90t + 70t + 70 = 100
\n" ); document.write( "160t = 100 - 70
\n" ); document.write( "160t = 30
\n" ); document.write( "t = 30/160
\n" ); document.write( "t = .1875 hrs, .1875(60) = 11.25 minutes A meets B, at 01:11:15 PM \n" ); document.write( "

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