document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=612700>Question 612700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this question? 5^(3x)=25^(2x+1)\r<BR>\n" );
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document.write( "The lesson that I am working on is about logarithms, so at some point I figure I need to use the log function or ln, but I don't know where.\r<BR>\n" );
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document.write( "So far this is what I have done... please tell me if I am on the right track.  THANK YOU!\r<BR>\n" );
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document.write( "5^(3x)=25^(2x+1)<BR>\n" );
document.write( "5^(3x)=5^(2(2x+1)<BR>\n" );
document.write( "5^(3x)=5^(4x+2)<BR>\n" );
document.write( "3x=4x+2<BR>\n" );
document.write( "-x=2<BR>\n" );
document.write( "x=-2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385678 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5^(3x)=25^(2x+1)<BR>\n" );
document.write( "5^(3x)=5^(2(2x+1)<BR>\n" );
document.write( "5^(3x)=5^(4x+2)<BR>\n" );
document.write( "3x=4x+2<BR>\n" );
document.write( "-x=2<BR>\n" );
document.write( "x=-2<BR>\n" );
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document.write( "Looks good to me.<BR>\n" );
document.write( "check the answer<BR>\n" );
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