document.write( "Question 612664: Melanie bought t things for d dollars. If the price was increased k dollars per item, how many items could Melanie by for 50 dollars?
\n" ); document.write( "
\n" ); document.write( "this is my work:\r
\n" ); document.write( "\n" ); document.write( "t=d t=k+d
\n" ); document.write( "t=k+50 \r
\n" ); document.write( "\n" ); document.write( "my answer: k+50
\n" ); document.write( " ------- items
\n" ); document.write( " t
\n" ); document.write( "

Algebra.Com's Answer #385647 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Melanie bought t things for d dollars.
\n" ); document.write( "Each item cost d/t dollars
\n" ); document.write( "-----------------------\r
\n" ); document.write( "\n" ); document.write( "If the price was increased k dollars per item
\n" ); document.write( "New price per item would be (d/t)+k
\n" ); document.write( "-------
\n" ); document.write( "How many items could Melanie by for 50 dollars?
\n" ); document.write( "# of items = (50 dollars)/[(d/t)+k]
\n" ); document.write( "= 50/[(d+tk)/t]
\n" ); document.write( "---
\n" ); document.write( "= 50t/(d+tk)
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===================
\n" ); document.write( "
\n" ); document.write( "
\n" );