document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=612623>Question 612623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide 184 into two parts such that 1/3 of one part may exceed 1/7 of the other part by 8. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385624 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Divide 184 into two parts such that 1/3 of one part may exceed 1/7 of the other part by 8.<BR>\n" );
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document.write( "Equatiion:<BR>\n" );
document.write( "(1/3)x -(1/7)(184-x) = 8<BR>\n" );
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document.write( "Multiply thru by 21 to get:<BR>\n" );
document.write( "7x - 3(184-x) = 168<BR>\n" );
document.write( "7x - 3*184 + 3x = 168<BR>\n" );
document.write( "10x = 168+3*184<BR>\n" );
document.write( "10x = 720<BR>\n" );
document.write( "x = 72<BR>\n" );
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document.write( "184-x = 112<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );