document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=612565>Question 612565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the fourth term of the sequence whose first term is a1=2 and whose nth term is an=4a(n-1)-11\r<BR>\n" );
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document.write( "My problem here is that i can't figure out how to use the nth term, what do you do with the info given? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #385566 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=385566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a recursive sequence. This means that you need to find each term before the fourth term a4 to find a4.\r<BR>\n" );
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document.write( "First term: a1 = 2\r<BR>\n" );
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document.write( "Second term: a2 = 4*a1-11 = 4*2-11 = 8-11 = -3\r<BR>\n" );
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document.write( "Third term: a3 = 4*a2-11 = 4*(-3)-11 = -12-11 = -23\r<BR>\n" );
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document.write( "Fourth term: a4 = 4*a3-11 = 4*(-23)-11 = -92-11 = <font color=\"red\">-103</font>\r<BR>\n" );
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document.write( "So the fourth term is a4 = <font color=\"red\">-103</font> </SPAN>\n" );
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